Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 492: 129

The intersection point is (2, 1). The solution set is $\{2\}$. .

The intersection point is (2, 1). The solution set is $\{2\}$. Verify by inserting $x=2$ $LHS=\log(2+3)+\log 2=\log 5+\log 2$ $=\log(5\cdot 2)=\log 10 =1=RHS$