College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 492: 128

Answer

The intersection point is $(\displaystyle \frac{11}{3},2)$. The solution set is $\displaystyle \{\frac{11}{3}\}$.

Work Step by Step

The intersection point is $(\displaystyle \frac{11}{3},2)$. The solution set is $\displaystyle \{\frac{11}{3}\}$. Verify by inserting $x=\displaystyle \frac{11}{3}$ $LHS= \displaystyle \log_{3}(3\cdot\frac{11}{3}-2)=\log_{3}(11- 2)=$ $=\log_{3}9=\log_{3}3^{2}=2=RHS$
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