Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 492: 137

$Doesn’t$ $make$ $sense$

Both equations can be solved by changing each to its logarithmic form. However, one of the equations can be further solved by using properties of logarithms to arrive at an integer solution: $$2^x = 15$$ $$\log_{2}15 = x$$ $$AND$$ $$2^x = 16$$ $$\log_{2}16 = x$$ $$\log_{2}2^4 = x$$ $$4\log_{2}2 = x$$ $$4 = x$$