College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 492: 130

Answer

The intersection point is (20, 2). The solution set is $\{20\}.$ .
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Work Step by Step

The intersection point is (20, 2). The solution set is $\{20\}.$ Verify by inserting $x=20$: $LHS= \log(x-15)+\log x=\log(20-15)+\log 20=$ $=\log 5+\log 20=\qquad ...$ Power rule $=\log(20\cdot 5)=\log 100=\log 10^{2}=2=RHS$
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