## College Algebra (6th Edition)

The intersection point is (20, 2). The solution set is $\{20\}.$ .
The intersection point is (20, 2). The solution set is $\{20\}.$ Verify by inserting $x=20$: $LHS= \log(x-15)+\log x=\log(20-15)+\log 20=$ $=\log 5+\log 20=\qquad ...$ Power rule $=\log(20\cdot 5)=\log 100=\log 10^{2}=2=RHS$