College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 492: 130

Answer

The intersection point is (20, 2). The solution set is $\{20\}.$ .

Work Step by Step

The intersection point is (20, 2). The solution set is $\{20\}.$ Verify by inserting $x=20$: $LHS= \log(x-15)+\log x=\log(20-15)+\log 20=$ $=\log 5+\log 20=\qquad ...$ Power rule $=\log(20\cdot 5)=\log 100=\log 10^{2}=2=RHS$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.