College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.3 - Page 478: 134

Answer

$x=\dfrac{2a+3b}{a-2b}$

Work Step by Step

$a(x-2)=b(2x+3)$ $,$ Solve for $x$: Evaluate the products on both sides of the equation: $ax-2a=2bx+3b$ Take $2bx$ to the left side and $2a$ to the right side: $ax-2bx=2a+3b$ Take out common factor $x$ from the left side: $x(a-2b)=2a+3b$ Take $a-2b$ to divide the right side: $x=\dfrac{2a+3b}{a-2b}$
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