Answer
False; $\frac{\log_{7}49}{\log_{7}7} = 2$
Work Step by Step
$$\frac{\log_{7}49}{\log_{7}7} = \log_{7}49 - \log_{7}7$$ $$\frac{\log_{7}7^2}{\log_{7}7} = \log_{7}7^2 - \log_{7}7$$ $$ \frac{2\log_{7}7}{\log_{7}7} = 2\log_{7}7 - log_{7}7$$ $$\frac{2(1)}{(1)} = 2(1) - (1)$$ $$2 \neq 1$$
