College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.3 - Page 478: 132

Answer

$\frac{f(x+h) – f(x)}{h} = \log_{b}(1+\frac{h}{x})^{\frac{1}{h}}$

Work Step by Step

$$f(x) = \log_{b}x$$ $f(x + h) = \log_{b}(x+h)$ $\frac{f(x+h) – f(x)}{h} = \frac{\log_{b}(x+h) - \log x}{h}$ $\frac{\log_{b}(x+h) - \log x}{h}$ $\frac{\log_{b}(\frac{x+h}{x})}{h}$ $\frac{1}{h}\log_{b}((\frac{1}{x})(x+h))$ $\log_{b}(1+\frac{h}{x})^{\frac{1}{h}}$
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