Answer
$\frac{f(x+h) – f(x)}{h} = \log_{b}(1+\frac{h}{x})^{\frac{1}{h}}$
Work Step by Step
$$f(x) = \log_{b}x$$
$f(x + h) = \log_{b}(x+h)$
$\frac{f(x+h) – f(x)}{h} = \frac{\log_{b}(x+h) - \log x}{h}$
$\frac{\log_{b}(x+h) - \log x}{h}$
$\frac{\log_{b}(\frac{x+h}{x})}{h}$
$\frac{1}{h}\log_{b}((\frac{1}{x})(x+h))$
$\log_{b}(1+\frac{h}{x})^{\frac{1}{h}}$