Answer
See below.
Work Step by Step
The Change-of-Base property says $\log_a{b}=\frac{\log_c{b}}{\log_c{a}}$
Thus $\log_{14}{283}=\frac{\ln{283}}{\ln{14}}$, then using our calculator the result is: $\approx2.139$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.3 - Page 478: 110
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