College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.3 - Page 478: 130

Answer

$\log_{7}9 = \frac{2A}{B}$

Work Step by Step

$$\log_{7}9$$ $$\frac{\log_{10}9}{\log_{10}7}$$ $$\frac{\log_{10}3^2}{\log_{10}7}$$ $$\frac{2\log 3}{\log 7}$$ $$\frac{2A}{B}$$
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