College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.7 - Page 430: 19

Answer

$ x=\displaystyle \frac{kz}{(y-w)}$ $y=\displaystyle \frac{kz}{x}+w$

Work Step by Step

$x$ varies directly as $z:\qquad x=kz$ $x$ varies inversely as $(y-w) :\displaystyle \qquad x=\frac{k}{(y-w)}$ Combined (jointly): $\displaystyle \qquad x=\frac{kz}{(y-w)}$ Solving for $y,$ $x=\displaystyle \frac{kz}{(y-w)}\qquad/\times(y-w)$ $x(y-w)=kz\qquad/\div x$ $y-w=\displaystyle \frac{kz}{x}\qquad/+w$ $y=\displaystyle \frac{kz}{x}+w$
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