College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.7 - Page 430: 16

Answer

$x=\displaystyle \frac{kyz}{w^{2}}$ $y=\displaystyle \frac{xw^{2}}{kz}$

Work Step by Step

$x$ varies directly as $y:\qquad x=ky$ $x$ varies directly as $z:\qquad x=kz$ $x$ varies inversely as $w^{2} :\displaystyle \qquad x=\frac{k}{w^{2}}$ Combined (jointly): $\displaystyle \qquad x=\frac{kyz}{w^{2}}$ Solving for $y,$ (multiply both sides with $\displaystyle \frac{w^{2}}{kz})$ $\displaystyle \frac{xw^{2}}{kz}=y$
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