College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.7 - Page 430: 13

Answer

$x=\displaystyle \frac{kz^{3}}{y}$ $y=\displaystyle \frac{kz^{3}}{x}$

Work Step by Step

$x$ varies directly as $z^{3}:\qquad x=kz^{3}$ $x$ varies inversely as $y :\displaystyle \qquad x=\frac{k}{y}$ Combined (jointly): $\displaystyle \qquad x=\frac{kz^{3}}{y}$ Solving for $y,$ multiply both sides by y (get it out of the denominator) $xy=kz^{3}\qquad/\div x$ $y=\displaystyle \frac{kz^{3}}{x}$
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