College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.7 - Page 430: 18

Answer

$x=kz(y-w)$ $y=\displaystyle \frac{x}{kz}+w$

Work Step by Step

$x$ varies directly as $z:\qquad x=kz$ $x$ varies directly as $(y-w):\qquad x=k(y-w)$ Combined (jointly): $\qquad x=kz(y-w)$ Solving for $y,$ $x=kz(y-w)\qquad/\div kz$ $\displaystyle \frac{x}{kz}=y-w\qquad/+w$ $y=\displaystyle \frac{x}{kz}+w$
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