College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.7 - Page 430: 11

Answer

$x=kyz$ $y=\displaystyle \frac{x}{kz}$

Work Step by Step

$x$ varies directly as $y:\qquad x=ky$ $x$ varies directly as $z:\qquad x=kz$ Combined (jointly): $\qquad x=kyz$ Solving for $y,$ divide both sides by ($kz)$ $\displaystyle \frac{x}{kz}=y$
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