College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.6 - Page 300: 122

Answer

$y = \sqrt {x+1}$

Work Step by Step

$x = y^{2} - 1$ $x + 1 = y^{2}$ $y = ±\sqrt {x+1}$ $y = \sqrt {x+1}$ (Since $y \geq 0$)
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