Answer
The statement is true because it satisfies the condition $(fg)(-x)=(fg)(x)$, making it an even function.
Work Step by Step
Below, it is demonstrated that the product of two functions is even.
$f(-x)=f(x)$
$g(-x)=g(x)$
$(fg)(x)=f(x)g(x)$
$(fg)(-x)=f(-x)g(-x)=f(x)g(x)$
$(fg)(-x)=(fg)(x)$
