Answer
$False$
Work Step by Step
$$f(x) = x^2-4$$ $$g(x) = \sqrt{x^2-4}$$
$f(g(x))= (\sqrt{x^2-4})^2 -4$
$f(g(x)) = (x^2-4) -4$
$f(g(x)) = x^2-8$
Therefore, $$f(g(5)) = (5)^2 -8 = 25-8 = 17$$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 2 - Functions and Graphs - Exercise Set 2.6 - Page 300: 114
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