Work Step by Step
False, those two are not necessarily equal. E.g. $f(x)=2x+1,g(x)=3x+8$. Then $f\circ g=f(g(x))=f(3x+2)=2(3x+8)+1=6x+17$, $g\circ f=g(f(x))=g(2x+1)=3(2x+1)+8=6x+11$ We can see that these two are not equal.
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