Answer
False.
Work Step by Step
False, those two are not necessarily equal. E.g. $f(x)=2x+1,g(x)=3x+8$.
Then $f\circ g=f(g(x))=f(3x+2)=2(3x+8)+1=6x+17$,
$g\circ f=g(f(x))=g(2x+1)=3(2x+1)+8=6x+11$
We can see that these two are not equal.