College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.6 - Page 300: 120

Answer

$$[(4,-2),(1,-1),(1,1),(4,2)]$$ This set of points does not represent a function.

Work Step by Step

$[(-2,4),(-1,1),(1,1),(2,4)]$, therefore, becomes: $$[(4,-2),(1,-1),(1,1),(4,2)]$$ Since the new set involves points where one value of $x$ has more than one value of $y$, we can say that this relation is not a function by definition.
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