Answer
$\{1-\sqrt 5, 1+\sqrt 5\}$
Work Step by Step
Step 1. Given the equation $x(x-2)=4$, we have $x^2-2x+1=5$ or $(x-1)^2=5$
Step 2. The above equation gives the solutions $x=1\pm\sqrt 5$ or in set form as $\{1-\sqrt 5, 1+\sqrt 5\}$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 1 - Summary, Review, and Test - Test - Page 206: 8
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