Answer
$\{-\frac{1}{2},2\}$
Work Step by Step
Step 1. Given the equation $2x^2-3x-2=0$, factor the left side to get $(2x+1)(x-2)=0$
Step 2. The above equation gives the solutions $x=-\frac{1}{2}, 2$ or in set form as $\{-\frac{1}{2},2\}$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 1 - Summary, Review, and Test - Test - Page 206: 5
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