College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Test - Page 206: 29

Answer

$x=\frac{y-y_1+mx_1}{m}$

Work Step by Step

Distribute the right side. Then add $mx_1$ on both sides. Then divide both sides by $m$. $y-y_1=m(x-x_1)$ for $x$ $y-y_1=mx-mx_1$ $y-y_1+mx_1=mx$ $x=\frac{y-y_1+mx_1}{m}$
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