College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Test - Page 206: 6

Answer

$x=\frac{\pm5\sqrt{3}+1}{3}$

Work Step by Step

$(3x-1)^2=75\\3x-1=\pm\sqrt{75}\\3x-1=\pm5\sqrt{3}\\3x-1+1=\pm5\sqrt{3}+1\\3x=\pm5\sqrt{3}+1\\3x/3=\frac{\pm5\sqrt{3}+1}{3}\\x=\frac{\pm5\sqrt{3}+1}{3}$
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