Answer
$\{5\}$
Work Step by Step
Step 1. Given the equation $\frac{2}{x-3}-\frac{4}{x+3}=\frac{8}{x^2-9}, x\ne\pm3$, multiply $(x-3)(x+3)$ on both sides to get $2(x+3)-4(x-3)=8$
Step 2. Simplify the above equation as $2x+6-4x+12=8$ or $-2x=-10$ to get the solution $x=5$ or in set form as $\{5\}$
