College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Review Exercises - Page 205: 97



Work Step by Step

$2\sqrt (x-1)=x$ Squaring on both sides. $4(x-1)=x^{2}$ $4x-4=x^{2}$ $x^{2}-4x+4=0$ By factoring, $(x-2)(x-2)=0$ $(x-2)^{2}=0$ $x-2=0$ $x=2$
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