## College Algebra (6th Edition)

$2$
$2\sqrt (x-1)=x$ Squaring on both sides. $4(x-1)=x^{2}$ $4x-4=x^{2}$ $x^{2}-4x+4=0$ By factoring, $(x-2)(x-2)=0$ $(x-2)^{2}=0$ $x-2=0$ $x=2$