Answer
$(-\infty,-2]$
Work Step by Step
$3(2x-1)-2(x-4)\geq 7+2(3+4x) \qquad ...$ distribute
$6x-3-2x+8\geq 7+6+8x \qquad ...$ simplify
$4x+5\geq 8x+13 \qquad ...$ add $-8\mathrm{x}-5$ to both sides, simplify
$-4x\geq 8 \qquad ...$ divide with -8. Negative, so the sign turns.
$x\leq-2$
The solution set is $(-\infty,-2]$
