College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Review Exercises - Page 205: 101

Answer

x=$\sqrt 2$, -$\sqrt 2$, or -3

Work Step by Step

x$^3$+3x$^2$-2x-6=0 x$^2$(x+3)-2(x+3)=0 (x$^2$-2)(x+3)=0 x=$\sqrt 2$, -$\sqrt 2$, or -3
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