College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Summary, Review, and Test - Review Exercises - Page 205: 87

Answer

x=3, -3, or 0.5

Work Step by Step

2x$^3$-x$^2$-18x+9=0 x$^2$(2x-1)-9(2x-1)=0 (x$^2$-9)(2x-1)=0 (x+3)(x-3)(2x-1)=0 x=-3, 3, or 0.5
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