College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Mid-Chapter Check Point - Page 165: 8

Answer

$$x = 3$$

Work Step by Step

We have $$\frac{3x}{4} -\frac{x}{3} + 1 = \frac{4x}{5} -\frac{3}{20}$$ As we see we have a lot of rational terms so we are going to multiply all the equation by the minimum common multiple of the denominators. The minimum common multiple of $3,4,5$ and $20$ is $60$ Multiplying each side of the equation by $60$ $$60*(\frac{3x}{4} -\frac{x}{3} + 1) = 60*(\frac{4x}{5} -\frac{3}{20})$$ $$\frac{60*(3x)}{4} -\frac{60*(x)}{3} + 60*(1) = \frac{60*(4x)}{5} -\frac{60*(3)}{20}$$ Simplifying each fraction $$15*(3x) - 20*(x) + 60*(1) = 12*(4x) - 3*(3)$$ $$45x - 20x + 60 = 48x - 9$$ Taking $x$ terms to the left side of the equation and numbers to the right $$45x - 20x - 48x = -9 - 60$$ Simplifying $$-23x = -69$$ Taking $-23$ which is multiplying to the other side dividing $$x = \frac{-69}{-23} = 3$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.