College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Mid-Chapter Check Point - Page 165: 15


Does not have x-intercepts.

Work Step by Step

We have $$y = 2x^2 + 26$$ To find the x-intercept we need to make $y=0$ and solve for $x$ $$2x^2 +26 = 0$$ Taking numbers to the right side of the equation $$2x^2 = -26$$ $$x^2 = \frac{-26}{2}$$ Simplifying and sending the power squared to the right side as square root $$x = \sqrt {-13}$$ As we know there is not square root of negative numbers, so the equation does not have x-intercepts.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.