## College Algebra (6th Edition)

We have $$y = 2x^2 + 26$$ To find the x-intercept we need to make $y=0$ and solve for $x$ $$2x^2 +26 = 0$$ Taking numbers to the right side of the equation $$2x^2 = -26$$ $$x^2 = \frac{-26}{2}$$ Simplifying and sending the power squared to the right side as square root $$x = \sqrt {-13}$$ As we know there is not square root of negative numbers, so the equation does not have x-intercepts.