#### Answer

Does not have x-intercepts.

#### Work Step by Step

We have $$y = 2x^2 + 26$$
To find the x-intercept we need to make $y=0$ and solve for $x$ $$2x^2 +26 = 0$$
Taking numbers to the right side of the equation $$2x^2 = -26$$ $$x^2 = \frac{-26}{2}$$
Simplifying and sending the power squared to the right side as square root $$x = \sqrt {-13}$$
As we know there is not square root of negative numbers, so the equation does not have x-intercepts.