College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Mid-Chapter Check Point - Page 165: 1

Answer

$$x = 6$$

Work Step by Step

We have $$-5 + 3(x+5) = 2(3x-4)$$ Note we have two parenthesis so we are going to do each multiplications in order two eliminate them $$ -5 +3*(x) + 3*(5) = 2*(3x) + 2*(-4)$$ Doing each multiplication taking in count the signs law $$-5 +3x + 15 = 6x - 8$$ If we take all the numbers to the right side of the equality and all the $x$ terms to the left side $$3x - 6x = -8 +5 - 15$$ Simplifying $$-3x = -18$$ In order to solve the equation we are going to take that $-3$ which is multiplying to the other side dividing $$x = -18/-3$$ Finally taking in count the signs law we have that $$x = 6$$
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