College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 164: 175

Answer

$t=\frac{-v_0±\sqrt {v_0^2-64s}}{32}$

Work Step by Step

Simply apply the given quadratic equation to the quadratic formula. $16t^2-v_0t+s=0$ $a=16, b=v_0, c=s$ $t=\frac{-v_0±\sqrt {v_0^2-4*16*s}}{2*16}$ $t=\frac{-v_0±\sqrt {v_0^2-64s}}{32}$
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