College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 164: 156


Given $x^2+6x+8=0$, we must first find two values that equal the third term when multiplied and the coefficient of the second term when added. Then we add or subtract these values from $x$ in two sets of parentheses, as shown below. Then we set each set equal to $0$ to get the values for $x$. $x^2+6x+8=0$ $(x+4)(x+2)=0$ $x=-4,-2$

Work Step by Step

$x^2+6x+8=0$ $(x+4)(x+2)=0$ $x=-4,-2$
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