## College Algebra (6th Edition)

Given $x^2+6x+8=0$, we must first find two values that equal the third term when multiplied and the coefficient of the second term when added. Then we add or subtract these values from $x$ in two sets of parentheses, as shown below. Then we set each set equal to $0$ to get the values for $x$. $x^2+6x+8=0$ $(x+4)(x+2)=0$ $x=-4,-2$
$x^2+6x+8=0$ $(x+4)(x+2)=0$ $x=-4,-2$