College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 164: 162

Answer

The real solutions of a quadratic equation are equals to the points where its graph "touches" the x-axis, that is, the points where $ y = 0 $

Work Step by Step

For example, the equation $x^2+x-2=0\longrightarrow(x+2)(x-1)=0$ We can see that the solutions are $x=-2$ and $x=1$ and in the graph we can see the points $(-2,0)$ and $(1,0)$.
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