College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5: 174

Answer

$x^{2}-2x-15=0$

Work Step by Step

Solution set is $\{-3,5\}$ $x=-3$ or $x=5$ $x+3=0$ or $x-5 = 0$ If $x+3=0$ or $x-5 = 0$ then $(x+3)(x-5)=0$ $x^{2}+3x-5x-15=0$ $x^{2}-2x-15=0$ This is the required quadratic equation whose solution set is $\{-3,5\}$
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