Answer
$-5+10i$
Work Step by Step
FOIL the terms in the parentheses, and then combine like terms. Be sure to turn $i^2$ into $-1$.
$(2+i)^2-(3-i)^2$
$(2+i)(2+i)-(3-i)(3-i)$
$4+2i+2i+i^2-(9-3i-3i+i^2)$
$4+4i+-1-(9-6i-1)$
$-5+10i$
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