College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.4 - Page 142: 25

Answer

a=$\frac{-24}{25} b=\frac{32}{25}$

Work Step by Step

Multiply the top and bottom of the term by the conjugate of the denominator. Then combine like terms and divide to simplify. Make sure to change $i^2$ to $-1$. $\frac{8i}{4-3i}$ $\frac{8i}{4-3i}(\frac{4+3i}{4+3i})$ $\frac{32i+24i^2}{4^2+3^2}$ $\frac{32i-24}{25}$ $\frac{-24}{25}+\frac{32}{25}i$
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