Answer
$-2\sqrt 6-2i\sqrt {10}$
Work Step by Step
Make the square roots positive by creating an imaginary number outside each negative one. Then distribute and multiply. Then simplify the radicals.
$\sqrt {-8}(\sqrt {-3}-\sqrt 5)$
$i\sqrt {8}(i\sqrt {3}-\sqrt 5)$
$-\sqrt {24}-i\sqrt {40}$
$-2\sqrt 6-2i\sqrt {10}$
