College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.4 - Page 142: 43


$24\sqrt {15}$

Work Step by Step

Make the square roots positive by creating an imaginary number outside them. Then multiply the terms in the parentheses and turn $i^2$ into $-1$. Then simplify the radical. $(3\sqrt {-5})(-4\sqrt {-12})$ $(3i\sqrt 5)(-4i\sqrt {12})$ $-12i^2\sqrt {60}$ $12\sqrt {60}$ $24\sqrt {15}$
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