Answer
$i+1$
Work Step by Step
Multiply the top and bottom of the term by the conjugate of the denominator. Then combine like terms and divide to simplify. Make sure to change $i^2$ to $-1$.
$\frac{2i}{1+i}$
$\frac{2i}{1+i}(\frac{1-i}{1-i})$
$\frac{2i-2i^2}{1-i+i-i^2}$
$\frac{2i-2(-1)}{1-(-1)}$
$\frac{2i+2}{2}$
$\frac{2(i+1)}{2}$
$i+1$
