## College Algebra (6th Edition)

$\frac{4}{x} = \frac{5}{2x} + 3 ; x \ne 0;$ $x = \frac{1}{2}$
$\frac{4}{x} = \frac{5}{2x} + 3 ; x \ne 0;$ Least Common Denominator is $2x$ Multiply both sides by $2x$ $2x(\frac{4}{x}) = 2x(\frac{5}{2x} + 3 ) ; x \ne 0;$ $8 = 2x(\frac{5}{2x}) + 2x(3)$ $8 = 5+ 6x$ $6x = 8-5$ $6x = 3$ $x = \frac{3}{6}$ $x = \frac{1}{2}$ Our only restriction is $x \ne 0$ $x = \frac{1}{2}$ is the solution of the equation.