College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2 - Page 118: 29

Answer

$x = 9.2$

Work Step by Step

$\frac{x+1}{3} = 5 - \frac{x+2}{7}$ $\frac{x+1}{3} = \frac{35-(x+2)}{7}$ $\frac{x+1}{3} = \frac{35-x-2}{7}$ $\frac{x+1}{3} = \frac{33-x}{7}$ Multiply both sides by 21 to clear fractions. $21(\frac{x+1}{3}) = 21(\frac{33-x}{7})$ $7(x+1)=3(33-x)$ $7x+7=99-3x$ Combine like terms. $7x+3x=99-7$ $10x=92$ $x=\frac{92}{10}$ $x = 9.2$
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