College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2 - Page 118: 26

Answer

$x=1$

Work Step by Step

$\frac{x+1}{4} = \frac{1}{6} + \frac{2-x}{3}$ Take LCD at the right hand side $\frac{x+1}{4} = \frac{1+2(2-x)}{6}$ $\frac{x+1}{4} = \frac{1+4-2x}{6}$ $\frac{x+1}{4} = \frac{5-2x}{6}$ Multiply both sides by 24 to clear fractions. $24(\frac{x+1}{4}) = 24(\frac{5-2x}{6})$ $6(x+1)= 4(5-2x)$ $6x+6= 20-8x$ Combine like terms. $6x+8x= 20-6$ $14x = 14$ $ x = \frac{14}{14}$ $x=1$
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