College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2: 28

Answer

$x=-19$

Work Step by Step

$5 + \frac{x-2 }{3} = \frac{x+3}{8}$ $\frac{15+x-2 }{3} = \frac{x+3}{8}$ $\frac{x+13 }{3} = \frac{x+3}{8}$ Multiply both sides by 24. $24(\frac{x+13 }{3}) = 24(\frac{x+3}{8})$ $8(x+13) = 3(x+3)$ $8x+104 = 3x+9$ $8x-3x = 9-104$ $5x = -95$ $x=-19$
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