College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2: 25

Answer

$x = \frac{33}{2}$

Work Step by Step

$\frac{x+3}{6} = \frac{3}{8} + \frac{x-5}{4}$ Take LCD at the right hand side $\frac{x+3}{6} = \frac{3+2(x-5)}{8} $ $\frac{x+3}{6} = \frac{3+2x-10}{8} $ $\frac{x+3}{6} = \frac{2x-7}{8} $ Multiply both sides by 48 to clear fractions. $48(\frac{x+3}{6}) = 48(\frac{2x-7}{8}) $ $8(x+3) = 6(2x-7) $ $8x+24 = 12x-42$ Combine like terms. $24+42= 12x-8x$ $66 = 4x$ $33 = 2x$ $x = \frac{33}{2}$
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