## College Algebra (6th Edition)

$x = \frac{33}{2}$
$\frac{x+3}{6} = \frac{3}{8} + \frac{x-5}{4}$ Take LCD at the right hand side $\frac{x+3}{6} = \frac{3+2(x-5)}{8}$ $\frac{x+3}{6} = \frac{3+2x-10}{8}$ $\frac{x+3}{6} = \frac{2x-7}{8}$ Multiply both sides by 48 to clear fractions. $48(\frac{x+3}{6}) = 48(\frac{2x-7}{8})$ $8(x+3) = 6(2x-7)$ $8x+24 = 12x-42$ Combine like terms. $24+42= 12x-8x$ $66 = 4x$ $33 = 2x$ $x = \frac{33}{2}$