#### Answer

$\log_b \dfrac{p}{qr}$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
Use the Laws of Logarithms to write the given expression, $
\log_b p-\log_b q-\log_b r
,$ as a single logarithm.
$\bf{\text{Solution Details:}}$
Grouping the last two terms, the expression above is equivalent to
\begin{array}{l}\require{cancel}
\log_b p-(\log_b q+\log_b r)
.\end{array}
Using the Product Rule of Logarithms, which is given by $\log_b (xy)=\log_bx+\log_by,$ the expression above is equivalent
\begin{array}{l}\require{cancel}
\log_b p-[\log_b (qr)]
.\end{array}
Using the Quotient Rule of Logarithms, which is given by $\log_b \dfrac{x}{y}=\log_bx-\log_by,$ the expression above is equivalent
\begin{array}{l}\require{cancel}
\log_b \dfrac{p}{qr}
.\end{array}