## College Algebra (11th Edition)

$\log_b \dfrac{p}{qr}$
$\bf{\text{Solution Outline:}}$ Use the Laws of Logarithms to write the given expression, $\log_b p-\log_b q-\log_b r ,$ as a single logarithm. $\bf{\text{Solution Details:}}$ Grouping the last two terms, the expression above is equivalent to \begin{array}{l}\require{cancel} \log_b p-(\log_b q+\log_b r) .\end{array} Using the Product Rule of Logarithms, which is given by $\log_b (xy)=\log_bx+\log_by,$ the expression above is equivalent \begin{array}{l}\require{cancel} \log_b p-[\log_b (qr)] .\end{array} Using the Quotient Rule of Logarithms, which is given by $\log_b \dfrac{x}{y}=\log_bx-\log_by,$ the expression above is equivalent \begin{array}{l}\require{cancel} \log_b \dfrac{p}{qr} .\end{array}