#### Answer

$\log_a\dfrac{xy}{m}$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
Use the Laws of Logarithms to write the given expression, $
\log_ax+\log_ay-\log_am
,$ as a single logarithm.
$\bf{\text{Solution Details:}}$
Using the Product Rule of Logarithms, which is given by $\log_b (xy)=\log_bx+\log_by,$ the expression above is equivalent
\begin{array}{l}\require{cancel}
\log_a(xy)-\log_am
.\end{array}
Using the Quotient Rule of Logarithms, which is given by $\log_b \dfrac{x}{y}=\log_bx-\log_by,$ the expression above is equivalent
\begin{array}{l}\require{cancel}
\log_a\dfrac{xy}{m}
.\end{array}