## College Algebra (11th Edition)

$\log_b\dfrac{km}{a}$
$\bf{\text{Solution Outline:}}$ Use the Laws of Logarithms to write the given expression, $\log_bk+\log_bm-\log_ba ,$ as a single logarithm. $\bf{\text{Solution Details:}}$ Using the Product Rule of Logarithms, which is given by $\log_b (xy)=\log_bx+\log_by,$ the expression above is equivalent to \begin{array}{l}\require{cancel} \log_b(km)-\log_ba .\end{array} Using the Quotient Rule of Logarithms, which is given by $\log_b \dfrac{x}{y}=\log_bx-\log_by,$ the expression above is equivalent to \begin{array}{l}\require{cancel} \log_b\dfrac{km}{a} .\end{array}