College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 3 - Section 3.3 - Zeros of Polynomial Functions - 3.3 Exercises - Page 315: 6

Answer

$x+1$ is a factor of $f(x)$

Work Step by Step

$x+1$ is a factor of $f(x)$, if $f(-1)=0$ By subtituting $x$ by $-1$, we get: $f(-1) = (-1)^3+6\times (-1)^2-2\times (-1) -7 \\f(-1) = 0$. Therefore, $x+1$ is a factor. $f(x)$.
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