College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Review Exercises - Page 279: 126

Answer

$(f\circ g)(3)=1$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To find the value of the given expression, $ \left( f\circ g \right)(3) ,$ use the definition of function composition. Then use the values in the given table. $\bf{\text{Solution Details:}}$ Using $(f\circ g)(x)=f(g(x)),$ then \begin{array}{l}\require{cancel} (f\circ g)(3)=f(g(3)) .\end{array} Based on the given table, when $x= 3 ,$ the value of $g(x)$ is $ -2 .$ Hence, $ g(3)=-2 .$ By substitution, the equation of the function composition above becomes \begin{array}{l}\require{cancel} (f\circ g)(3)=f(g(3)) \\\\ (f\circ g)(3)=f(-2) .\end{array} Based on the given table, when $x= -2 ,$ the value of $f(x)$ is $ 1 .$ Hence, $ f(-2)=1 .$ By substitution, the equation of the function composition above becomes \begin{array}{l}\require{cancel} (f\circ g)(3)=f(g(3)) \\\\ (f\circ g)(3)=f(-2) \\\\ (f\circ g)(3)=1 .\end{array}
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